Mathematics MCQS for class 12 with Answers

The solution of differential equation dy/dx = 1/?x2-1 is:

cot hx + c

y = cosh

^{-1}x + cy = sinh-1 x+c

y = tanh

^{-1}x+ cSubstitution for the integrals involving the expression ?a

^{2}-x can be:x = a sin?

x =a cosec?

x = a tan?

x = a cot?

-? e

^{cotx-1}/1+x^{2}dx =e

^{secx}+ ce

^{tan-1x}+ ce

^{cot-1x}+ ce

^{tanx}+ c?e

^{ax}[af(x)+f'(x)]dx=________1/a f(x) + c

1/ae

^{ax f(x)+c}e

^{ax}f(x) + c1/e

^{ax }+ c?e

^{tan-1}/1-x^{2}dx =e

^{tan-1}x + ce

^{2x}+ctanx e

^{x}+ce

^{cotx}+ cThe inverse process of differentiation is called:

None of these

Integration

Anti-derivative

Both (a)&(b)

?

^{3}_{-1}x^{3}dx =28

18

80

20

? Cosx /Sinx ln Sinx dx =________

Tan x + c

x Sin

^{-1}x + ?(1-x^{2}) + c ln(ln Sin x) + cln(ln Cos x) + c

ln Sin x

The solution of xdy/dx = 1 + y is

y= cx

1/a ln(ax+b)+c

None of these

y= cx – 1

The solution of dy/dx = -y is ________

y=ce

^{x}y=e

^{x}y=e

^{-x}y=ce

^{-x}*Continue Reading Go to Next Page*