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6 + 13 =
Solve this simple math problem and enter the result. E.g. for 1+3, enter 4.

\(\frac{d}{{dx}}{({x^3} + 1)^9} = \)

\(9{({x^3} + 1)^8}(3{x^2})\)

\(\frac{{({x^3} + 1){}^9}}{{3{x^2}}}\)

\(9{x^2}{(3{x^2} + 1)^8}\)

\(9{({x^3} + 1)^8}\)