If x = a(t-sint), y=a(1+cost), then \(\frac{{dy}}{{dx}}\) is given by:

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4 + 15 =
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If x = a(t-sint), y=a(1+cost), then \(\frac{{dy}}{{dx}}\) is given by:

\(\cot \frac{1}{2}\)

\( - \cot \frac{1}{2}\)

\( - \tan \frac{1}{2}\)

\(\tan \frac{1}{2}\)