Mode of 1,3,5,7,9,11,13,15 is:
Mode of 1,3,5,7,9,11,13,15 is:
9 | |
11 | |
No Mode | |
7 |
en
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(111)2 +(10)2 =
(111)2 +(10)2 =
(1100)2 | |
(1001)2 | |
(1011)2 | |
(1101)2 |
√81/100
√81/100
10-Sep | |
9/100 | |
10-Mar | |
91/10 |
Power set of {x} is:
Power set of {x} is:
{{0},{x}} | |
{{,},{x}} | |
{{},x} | |
{{∅},{x}} |
Which of the following numbers is a perfect square?
Which of the following numbers is a perfect square?
24 | |
14 | |
9 | |
12 |
Number of vertices of a pentagon is.
Number of vertices of a pentagon is.
6 | |
4 | |
5 | |
3 |
The surface area of a sphere is 154 m. its radius will be:
The surface area of a sphere is 154 m. its radius will be:
3.6 m | |
3.5 m | |
3.9 m | |
3.4 m |
Factorization of _2x2+xy2+3xy is :
Factorization of _2x2+xy2+3xy is :
-xy(2x+y+3) | |
xy(2x-y-3) | |
-xy(2x-y-3) | |
xy(2x+y+3) |
Square of 0.01 is:
Square of 0.01 is:
0.001 | |
0.01 | |
0.00001 | |
0.0001 |
(4x3-6x+6)÷ (-x3+3x-3)=
(4x3-6x+6)÷ (-x3+3x-3)=
3x3+3x-3 | |
3x3-3x-3 | |
3x3-3x+3 | |
3x3+3x+3 |
The frequency of the class interval of the data 12,12,14,13,15,11 will be:
The frequency of the class interval of the data 12,12,14,13,15,11 will be:
2 | |
5 | |
6 | |
4 |
Square of 0.6 is:
Square of 0.6 is:
0.036 | |
3.6 | |
0.0036 | |
0.36 |
The mode of data 2,9,12,2,6,3,21,12 is:
The mode of data 2,9,12,2,6,3,21,12 is:
2,12 | |
12,9 | |
12 | |
2 |
In equations 3x+5y = 0 and 3x +4y = 0 , the values of x and y are.
In equations 3x+5y = 0 and 3x +4y = 0 , the values of x and y are.
x=0,y=0 | |
x=3,y=3 | |
x=1,y=1 | |
y=3,x=1 |
20 men complete a work in 10 days . IN how many days, 40 men will complete the same work.
20 men complete a work in 10 days . IN how many days, 40 men will complete the same work.
40 | |
20 | |
5 | |
10 |
The number of variables in polynomial, 4x2 -2y -1 is:
The number of variables in polynomial, 4x2 -2y -1 is:
4 | |
2 | |
1 | |
3 |
In equation 3x +5y =0 and 3x +4y =0, the values of x and y are:
In equation 3x +5y =0 and 3x +4y =0, the values of x and y are:
y=3x=1 | |
x=1,y=1 | |
x=0,y=0 | |
x=3,y=4 |
(111)2+(111)2=
(111)2+(111)2=
(1100)2 | |
(1010)2 | |
(1110)2 | |
(1001)2 |
By eliminating "x" from x2 = a+c and x2 =b, we get:
By eliminating "x" from x2 = a+c and x2 =b, we get:
a-c=-b | |
a+c=-b | |
a-c=b | |
a+c=b |
How many canadian dollars are in Rs.5092? ( 1 canadian dollar = Rs.76)
How many canadian dollars are in Rs.5092? ( 1 canadian dollar = Rs.76)
5016 | |
67 | |
76 | |
5168 |